Q#1: Bending of a beam occurs due to:
(A) Transverse load applied perpendicular to the axis
(B) Axial load only
(C) Torque only
(D) Mass only
Answer: (A) Transverse load applied perpendicular to the axis
Q#2: Bending stress is:
(A) Normal stress developed due to bending moment
(B) Shear stress only
(C) Axial stress only
(D) Work only
Answer: (A) Normal stress developed due to bending moment
Q#3: Maximum bending stress occurs:
(A) At the extreme fibers of the beam
(B) At the neutral axis
(C) Mid-span only
(D) Mass only
Answer: (A) At the extreme fibers of the beam
Q#4: Neutral axis of a beam is:
(A) Line along which fibers experience zero stress
(B) Line of maximum stress
(C) Mid-point only
(D) Mass only
Answer: (A) Line along which fibers experience zero stress
Q#5: Flexure formula for bending stress:
(A)
𝜎
𝑀
𝑦
𝐼
σ=
I
My
(B)
𝜎
𝐹
/
𝐴
σ=F/A
(C) Torque only
(D) Mass only
Answer: (A)
𝜎
𝑀
𝑦
𝐼
σ=
I
My
Q#6: In flexure formula,
𝑀
M represents:
(A) Bending moment at the section
(B) Shear force only
(C) Torque only
(D) Work only
Answer: (A) Bending moment at the section
Q#7: In flexure formula,
𝑦
y represents:
(A) Distance from neutral axis
(B) Length of beam
(C) Torque only
(D) Mass only
Answer: (A) Distance from neutral axis
Q#8: In flexure formula,
𝐼
I represents:
(A) Moment of inertia of the cross-section about neutral axis
(B) Polar moment of inertia
(C) Mass only
(D) Torque only
Answer: (A) Moment of inertia of the cross-section about neutral axis
Q#9: Bending moment in a simply supported beam with central point load:
(A) Maximum at mid-span
(B) Zero at mid-span
(C) Maximum at supports
(D) Mass only
Answer: (A) Maximum at mid-span
Q#10: Bending stress is:
(A) Directly proportional to bending moment and distance from neutral axis
(B) Shear stress only
(C) Mass only
(D) Torque only
Answer: (A) Directly proportional to bending moment and distance from neutral axis
Q#11: Neutral axis passes through:
(A) Centroid of the cross-section
(B) Maximum fiber
(C) Mass only
(D) Torque only
Answer: (A) Centroid of the cross-section
Q#12: Section modulus of a beam:
(A)
𝑍
𝐼
𝑦
max
Z=
y
max
I
(B)
𝑍
𝐴
/
𝐿
Z=A/L
(C) Mass only
(D) Torque only
Answer: (A)
𝑍
𝐼
𝑦
max
Z=
y
max
I
Q#13: Maximum bending stress using section modulus:
(A)
𝜎
max
𝑀
/
𝑍
σ
max
=M/Z
(B)
𝜎
max
𝐹
/
𝐴
σ
max
=F/A
(C) Torque only
(D) Mass only
Answer: (A)
𝜎
max
𝑀
/
𝑍
σ
max
=M/Z
Q#14: Bending produces:
(A) Tensile stress on one fiber and compressive stress on opposite fiber
(B) Shear only
(C) Axial stress only
(D) Mass only
Answer: (A) Tensile stress on one fiber and compressive stress on opposite fiber
Q#15: Maximum bending moment in a cantilever beam with end load:
(A) At the fixed support
(B) At free end
(C) Mid-span
(D) Mass only
Answer: (A) At the fixed support
Q#16: Bending stress distribution is:
(A) Linear from neutral axis to extreme fiber
(B) Uniform
(C) Parabolic
(D) Mass only
Answer: (A) Linear from neutral axis to extreme fiber
Q#17: Curvature of a beam is:
(A) Reciprocal of radius of curvature
(B) Bending moment
(C) Shear stress only
(D) Mass only
Answer: (A) Reciprocal of radius of curvature
Q#18: Maximum bending stress in a rectangular section:
(A)
𝜎
max
6
𝑀
𝑏
ℎ
2
σ
max
=
bh
2
6M
(B)
𝜎
max
𝐹
/
𝐴
σ
max
=F/A
(C) Torque only
(D) Mass only
Answer: (A)
𝜎
max
6
𝑀
𝑏
ℎ
2
σ
max
=
bh
2
6M
Q#19: Moment of inertia for rectangular cross-section:
(A)
𝐼
𝑏
ℎ
3
12
I=
12
bh
3
(B)
𝐼
𝜋
𝑑
4
/
64
I=πd
4
/64
(C) Mass only
(D) Torque only
Answer: (A)
𝐼
𝑏
ℎ
3
12
I=
12
bh
3
Q#20: In pure bending:
(A) Shear force is zero along the section
(B) Shear stress is maximum
(C) Torque only
(D) Mass only
Answer: (A) Shear force is zero along the section