Q#1: The area moment of inertia is a measure of:
(A) A shapeβs resistance to bending
(B) Mass only
(C) Torque only
(D) Length only
Answer: (A) A shapeβs resistance to bending
Q#2: The second moment of area about an axis is given by:
(A)
πΌ
β«
π¦
2
π
π΄
I=β«y
2
dA
(B)
πΌ
β«
π₯
π
π΄
I=β«xdA
(C)
πΌ
β«
π
π΄
I=β«dA
(D)
πΌ
β«
π₯
π¦
π
π΄
I=β«xydA
Answer: (A)
πΌ
β«
π¦
2
π
π΄
I=β«y
2
dA
(Where y = distance from axis, dA = area element)
Q#3: The moment of inertia of a rectangle about its base is:
(A)
πΌ
π
β
3
3
I=
3
bh
3
β
(B)
πΌ
π
β
2
2
I=
2
bh
2
β
(C)
πΌ
π
β
3
I=bh
3
(D)
πΌ
π
3
β
3
I=
3
b
3
h
β
Answer: (A)
πΌ
π
β
3
3
I=
3
bh
3
β
(b = width, h = height)
Q#4: The moment of inertia of a rectangle about its centroidal axis parallel to base is:
(A)
πΌ
π
β
3
12
I=
12
bh
3
β
(B)
πΌ
π
β
2
2
I=
2
bh
2
β
(C)
πΌ
π
β
3
I=bh
3
(D)
πΌ
π
3
β
3
I=
3
b
3
h
β
Answer: (A)
πΌ
π
β
3
12
I=
12
bh
3
β
Q#5: The moment of inertia of a circle about its centroidal axis is:
(A)
πΌ
π
π
4
4
I=
4
ΟR
4
β
(B)
πΌ
π
π
3
I=ΟR
3
(C)
πΌ
π
π
2
I=ΟR
2
(D)
πΌ
π
π
5
5
I=
5
ΟR
5
β
Answer: (A)
πΌ
π
π
4
4
I=
4
ΟR
4
β
Q#6: The moment of inertia of a circle about an axis through the diameter is:
(A)
πΌ
π
π
4
8
I=
8
ΟR
4
β
(B)
πΌ
π
π
4
4
I=
4
ΟR
4
β
(C)
πΌ
π
π
3
I=ΟR
3
(D)
πΌ
π
π
2
I=ΟR
2
Answer: (A)
πΌ
π
π
4
8
I=
8
ΟR
4
β
Q#7: The polar moment of inertia of a circle about its center is:
(A)
π½
π
π
4
2
J=
2
ΟR
4
β
(B)
π½
π
π
4
4
J=
4
ΟR
4
β
(C)
π½
π
π
3
J=ΟR
3
(D)
π½
π
π
2
J=ΟR
2
Answer: (A)
π½
π
π
4
2
J=
2
ΟR
4
β
Q#8: The moment of inertia of a thin rod about its centroid perpendicular to length is:
(A)
πΌ
πΏ
3
12
I=
12
L
3
β
(B)
πΌ
πΏ
2
2
I=
2
L
2
β
(C)
πΌ
πΏ
4
4
I=
4
L
4
β
(D)
πΌ
πΏ
3
I=L
3
Answer: (A)
πΌ
πΏ
3
12
I=
12
L
3
β
(L = length, unit width assumed 1)
Q#9: The moment of inertia of a thin rod about its end is:
(A)
πΌ
πΏ
3
3
I=
3
L
3
β
(B)
πΌ
πΏ
3
12
I=
12
L
3
β
(C)
πΌ
πΏ
2
2
I=
2
L
2
β
(D)
πΌ
πΏ
3
I=L
3
Answer: (A)
πΌ
πΏ
3
3
I=
3
L
3
β
Q#10: Parallel axis theorem is used to:
(A) Find the moment of inertia about any axis parallel to centroidal axis
(B) Measure mass
(C) Measure torque only
(D) Calculate stress only
Answer: (A) Find the moment of inertia about any axis parallel to centroidal axis
Q#11: The parallel axis theorem formula is:
(A)
πΌ
πΌ
π
+
π΄
π
2
I=I
c
β
+Ad
2
(B)
πΌ
πΌ
π
β
π΄
π
2
I=I
c
β
βAd
2
(C)
πΌ
πΌ
π
β
π
2
I=I
c
β
β
d
2
(D)
πΌ
π΄
/
π
2
I=A/d
2
Answer: (A)
πΌ
πΌ
π
+
π΄
π
2
I=I
c
β
+Ad
2
(I = moment about new axis, Ic = centroidal, A = area, d = distance)
Q#12: The perpendicular axis theorem states:
(A)
πΌ
π§
πΌ
π₯
+
πΌ
π¦
I
z
β
=I
x
β
+I
y
β
for a lamina in xy-plane
(B)
πΌ
π§
πΌ
π₯
β
πΌ
π¦
I
z
β
=I
x
β
βI
y
β
(C)
πΌ
π§
πΌ
π₯
β
πΌ
π¦
I
z
β
=I
x
β
β
I
y
β
(D)
πΌ
π§
πΌ
π₯
/
πΌ
π¦
I
z
β
=I
x
β
/I
y
β
Answer: (A)
πΌ
π§
πΌ
π₯
+
πΌ
π¦
I
z
β
=I
x
β
+I
y
β
for a lamina in xy-plane
Q#13: The moment of inertia of a hollow circular section about its centroidal axis is:
(A)
πΌ
π
(
π
π
4
β
π
π
4
)
4
I=
4
Ο(R
o
4
β
βR
i
4
β
)
β
(B)
πΌ
π
(
π
π
4
+
π
π
4
)
4
I=
4
Ο(R
o
4
β
+R
i
4
β
)
β
(C)
πΌ
π
(
π
π
2
β
π
π
2
)
I=Ο(R
o
2
β
βR
i
2
β
)
(D)
πΌ
π
(
π
π
3
β
π
π
3
)
3
I=
3
Ο(R
o
3
β
βR
i
3
β
)
β
Answer: (A)
πΌ
π
(
π
π
4
β
π
π
4
)
4
I=
4
Ο(R
o
4
β
βR
i
4
β
)
β
(Ro = outer radius, Ri = inner radius)
Q#14: For a composite area, the moment of inertia can be found by:
(A) Adding or subtracting the moments of individual areas
(B) Measuring edges only
(C) Using torque only
(D) Using mass only
Answer: (A) Adding or subtracting the moments of individual areas
Q#15: The centroidal axis of a section passes through:
(A) The centroid of the section
(B) Edge only
(C) Maximum stress point
(D) Random point
Answer: (A) The centroid of the section
Q#16: The neutral axis of a beam in bending passes through:
(A) The centroid of the cross-section
(B) Base only
(C) Top only
(D) Random point
Answer: (A) The centroid of the cross-section
Q#17: The moment of inertia of a rectangle about an axis along its width at centroid is:
(A)
πΌ
π
β
3
12
I=
12
bh
3
β
(B)
πΌ
π
β
3
3
I=
3
bh
3
β
(C)
πΌ
π
β
3
I=bh
3
(D)
πΌ
β
3
12
I=
12
h
3
β
Answer: (A)
πΌ
π
β
3
12
I=
12
bh
3
β
Q#18: The moment of inertia of a triangle about its base is:
(A)
πΌ
π
β
3
3
I=
3
bh
3
β
(B)
πΌ
π
β
2
2
I=
2
bh
2
β
(C)
πΌ
π
β
3
I=bh
3
(D)
πΌ
π
3
β
3
I=
3
b
3
h
β
Answer: (A)
πΌ
π
β
3
3
I=
3
bh
3
β
Q#19: The centroidal moment of inertia of a circular sector about its base:
(A)
πΌ
π
4
8
I=
8
R
4
β
approx
(B)
πΌ
π
2
I=R
2
(C)
πΌ
π
3
I=R
3
(D)
πΌ
π
4
4
I=
4
R
4
β
Answer: (A)
πΌ
π
4
8
I=
8
R
4
β
approx
Q#20: Area moment of inertia is important in:
(A) Beam bending, shaft design, and structural analysis
(B) Mass measurement only
(C) Torque calculation only
(D) Temperature analysis only
Answer: (A) Beam bending, shaft design, and structural analysis