Ohm’s Law and Kirchhoff’s Laws MCQs

Q1: Ohm’s Law states that:
(A) Current is proportional to resistance
(B) Voltage is proportional to resistance
(C) Current is proportional to voltage
(D) Power is proportional to voltage
Answer: (C) Current is proportional to voltage

Q2: The mathematical expression for Ohm’s Law is:
(A) $I = V times R$
(B) $V = I times R$
(C) $R = V times I$
(D) $P = I^2 R$
Answer: (B) $V = I times R$

Q3: If the resistance of a circuit is doubled and the voltage remains constant, the current will:
(A) Double
(B) Remain the same
(C) Halve
(D) Increase fourfold
Answer: (C) Halve

Q4: A resistor has a resistance of $10 , Omega$. If a $5 , A$ current flows through it, the voltage across the resistor is:
(A) 5 V
(B) 10 V
(C) 50 V
(D) 100 V
Answer: (C) 50 V

Q5: The unit of resistance is:
(A) Volt
(B) Ohm
(C) Ampere
(D) Watt
Answer: (B) Ohm

Kirchhoff’s Laws MCQs

Q6: Kirchhoff’s Current Law (KCL) states that:
(A) The total current entering a junction equals the total current leaving the junction
(B) The sum of all currents in a loop is zero
(C) Current is inversely proportional to resistance
(D) Total current is proportional to voltage
Answer: (A) The total current entering a junction equals the total current leaving the junction

Q7: Kirchhoff’s Voltage Law (KVL) states that:
(A) The total voltage in a circuit is equal to zero
(B) The sum of all voltages around a closed loop equals zero
(C) Voltage is directly proportional to resistance
(D) Voltage and current are inversely proportional
Answer: (B) The sum of all voltages around a closed loop equals zero

Q8: In Kirchhoff’s Voltage Law (KVL), the algebraic sum of potential differences in a closed loop is zero because:
(A) Energy is conserved
(B) Charge is conserved
(C) Voltage is constant
(D) Current is constant
Answer: (A) Energy is conserved

Q9: Kirchhoff’s Current Law (KCL) is based on the principle of:
(A) Conservation of energy
(B) Conservation of charge
(C) Conservation of mass
(D) Conservation of momentum
Answer: (B) Conservation of charge

Q10: If three currents $I_1 = 2,A$, $I_2 = 3,A$, and $I_3 = 1,A$ enter a junction, the current leaving the junction is:
(A) 6 A
(B) 2 A
(C) 1 A
(D) 0 A
Answer: (A) 6 A